""Death in a distant land"." Topic

Hello everyone,

Someone has the old rules: "Death in a distant land".?

If yes, there is something I don't understand, it's the text under the "casualty table" table on page 11, it says:

"Explanations: Throw two d6, one red, one white.

The red is the first digit, the white the second.

You must throw under the number indicated at the junction of the number of figures firing and the fire effect total.

Thus 10 men firing at a factor of 9,show the number 52.

A throw of 5 or under on the red die means you have scored a hit.

Throw the white dice also to discover the number of casualties inflicted.

For each 10 you are below the required number you have killed an addition figure.

Therefore 5 and 2 means one casualty, 4 & 2 two dead ect…"

For the red dice I understood everything but for the white dice, I don't understand anything…

Please help me, thank you all.

I do not know these rules and not having the chart makes it impossible to determine how the 52 was determined.

Nonetheless, for the last part ( the English could be more precise) the red 4 is the number of hits (wounds), the white 2 is the resulting 2 kills that are removed from play. The remaining 2 are presumably wounded and remain in play.

I hope this helps.

On the table of losses, at the crossroads of 10 shooters and a factor of 9 you find 52.

Do we throw a white 10 die and a red 10 die at the same time.

A throw of 5 or under on the red die means you have scored a hit or a wounded (Why a wounded ?) and a 2 with the white die indicates the number of kills?

Or 2 killed in this example??

What is The Remaining 2 you're talking about?

I don't have the rules, but from the example I assume it means the first (red) die is the tens column and the second (white) die is the ones column, so the result will be between 11 and 66, as it says d6, which is shorthand for a six-sided die.

You need a 5 or less on the tens column (the red die) for a hit.

So with 52 as the target number for success, if you roll that number exactly it means a hit (5 or less needed on the red die) that causes 1 casualty, if you roll 42 it means 2 casualties (as the result is 10 less than the target number), if you roll 32 it would be 3 casualties (as the 10 less than the target number has occurred twice), etc.

53-66 no effect
43-52 1 casualty
33-42 2 casualties
23-32 3 casualties
13-22 4 casualties
11-12 5 casualties

Thank you, Mr. Steve Wilcox!

Ok understood for the result for the red die, but then what is the white die for, if only the result of the red die modifies the number of losses?

It says "Throw the white dice also to discover the number of casualties inflicted.".

So let's imagine a result of 51 with both dice, so 5 on the red die = 1 victim and 1 on the white die = 1 other victim as indicated by the die = a total of 2 victims?

For example 15 figures firing at a factor of 1, show the number 33.

Also a throw of 2 or under on the red die mean that I scored a hit and made 2 victims and a throw of 2 on the white die, 2 additional victims? = a total of 4 victims?

Note that for the "Campaign system", when there are 10 losses, 4 are currently killed, 2 badly wounded, 2 walking wounded and the last 2 minor hits and bruising.

I understood ?

Ok understood for the result for the red die, but then what is the white die for, if only the result of the red die modifies the number of losses?

Think of the red die as the first digit of a 2 digit number, and the white die as the second digit of a 2 digit number.

The red die determines if there was a hit or not (5 or less in the example).

So 52.

The 2 dice together when compared to the target number (52 in the example) determine the number of casualties.

So 52.

The base result of an effective hit is 1 casualty, but for each 10 you roll less than the target number, you inflict an additional casualty.

So if you roll a 42 (4 on the red die, 2 on the white die), you inflict an additional casualty as 42 is 10 less than 52.

If you rolled a 32, that would mean 2 additional casualties, as this is 20 lower than the target number of 52.

It says "Throw the white dice also to discover the number of casualties inflicted.".

This just means roll both the dice to get a 2 digit number to compare to the target number.

For example 15 figures firing at a factor of 1, show the number 33.

Also a throw of 2 or under on the red die mean that I scored a hit and made 2 victims and a throw of 2 on the white die, 2 additional victims? = a total of 4 victims?

For a target number of 33 you would have to roll 3 or less on the red die and then compare the result from both dice to the target number.

It would be like this:
24-33 1 casualty
12-23 2 casualties (10 less than 33)
11-13 3 casualties (20 less than 33)

Note that for the "Campaign system", when there are 10 losses, 4 are currently killed, 2 badly wounded, 2 walking wounded and the last 2 minor hits and bruising.

I don't know how the campaign determines this.

Thank you Mr. Steve Wilcox,

So if I understood correctly the white die does not indicate additional losses.

The red die must be equal to or less than the tens digit indicated on the number on the board to obtain a hit and a loss, after if the total of the two dice is lower by 10 to the number indicated on the table, there is one more loss…

Example 42 for 52 = 2 losses, 32 for 52 = 3 losses, etc.

To see if I understood, another example:

18 shooters with a final factor of 12 gives us a result of 74.

With a die roll of 81 (I use 2 dice of 10, one red and one white) there are no losses, but with a roll of 21 there are 6 losses.

For kills and types of wounded in the campaign system, it's automatic every time you have 10 casualties.

I love this rule like all those published by SERVICE ACTIVE PRESS because they have super playful and so original game systems that for "Death in a distant land" I had understood nothing about the loss system! LOL §

This rule seems to be 1 to 1 without it being implicitly specified and no size is given for the bases of the miniatures.

For the armament, the firing factors of the "Charleville" musket are more powerful from 20% to 50% than those of the "Brown Bess" musket according to the firing ranges which are identical for the two weapons.

I had never seen that, however it is a rule written by two British.

This rule is indicated for the SYW in America and the AWI, but by adding a factor of + 1 in melee for lancers (mounted) and cavalry wearing cuirass, I think to use it for armies in Europe before 1792!

The only problem is for the indians who don't have a bow or throwing weapons???

I'll have to think about that

In artillery, there are only firing factors for 6 lb guns maximum, firing factors for 12 lb guns maximum and howitzers…

To see if I understood, another example:

18 shooters with a final factor of 12 gives us a result of 74.

With a die roll of 81 (I use 2 dice of 10, one red and one white) there are no losses, but with a roll of 21 there are 6 losses.

Yes, any roll between 15 and 24 would be 6 casualties as you're subtracting from the target number of 74.
If you rolled between 11 and 14 that would be 7 casualties.

Basically, if you roll equal to the target number it's 1 casualty, and for every 10 less than the target number you're rolling against, it's 1 additional casualty.

The initial example said to use 6-sided dice ("Throw two d6, one red, one white."), but that's up to you.

I know but the maximum loss result on the board is 84 so we have to use two dice of 10..