
"Statistics question" Topic
8 Posts
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OldGrenadier  | 19 Oct 2009 6:14 p.m. PST |
What is the contradiction called in the following circumstance: Player 1 has a higher batting average than Player 2 over a two-week period, but the cumulative results of Player 2 are better. In other words, Player 2 is more consistant. What is this in statistical terms? |
Murphy  | 19 Oct 2009 6:31 p.m. PST |
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Murphy  | 19 Oct 2009 6:32 p.m. PST |
dont mind me I am on my second bottle of wine tonight
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| Mardaddy | 19 Oct 2009 7:05 p.m. PST |
Quantitive vs qualitative? Ack – that ain't it. Read the question over a couple more times
umm, hand-picked time-frame average vs seasonal average? |
| adub74 | 20 Oct 2009 7:23 a.m. PST |
hmm
Let me see if I have your question right. Player 1, batting ninth in the order, goes to bat 10 times and gets 3 hits for a .300 average. Player 2, batting lead off, goes to bat 15 times and gets 4 hits for a .267 average. Player 2 has more hits than Player 1 but a lower average? I don't know what statistics calls it, but I call it the difference between a sum and an average. And no, Player 2 is not more consistant; he simply had more opprotunities. |
| Streitax | 20 Oct 2009 12:06 p.m. PST |
It's called Simpson's Paradox. Also sprach der statistician. |
| StarfuryXL5 | 20 Oct 2009 9:03 p.m. PST |
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| Last Hussar | 28 Oct 2009 4:26 a.m. PST |
In Cricket your average is the total number of runs scored, divided by total number of innings- effectively very similar to baseball, as you only get one 'at bat' in any innings. However these stats can be thrown. Bear with me on this (or skip to the last para if you know cricket) If you don't know in cricket- you don't have a diamond, instead the batter runs to and from the bowler's (=pitcher) end. Standing at the bowlers end is another batsman, who becomes 'on strike' if there is an odd number of runs (1,3,5). This means you have to have 2 batsmen in the middle at any one time. All 11 players bat, usually in order of ability, with the bowlers tending to be at 8, 9, 10 and 11 (the 'tail'). Once 10 men are out the 11th has no partner, so the innings is over, BUT the final man is not himself out. So his score is counted, but he does not get a 'wicket' against him. So for instance Total career runs=1000, Innings equal 50, Average= 20 If 10 of those innings he was 'Not Out' then 1000/40 =25 If a batman is never out (most likely for a lowly 10 or 11, an opener rarely 'carries his bat'), but always runs out of partners, his total would be divided by 0
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